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Solve for 
y.
Assume the equation has a solution for 
y.

{:[12 y+d=-19 y+t],[y=◻]:}

Solve for y y .\newlineAssume the equation has a solution for y y .\newline12y+d=19y+ty= \begin{array}{l} 12 y+d=-19 y+t \\ y=\square \end{array}

Full solution

Q. Solve for y y .\newlineAssume the equation has a solution for y y .\newline12y+d=19y+ty= \begin{array}{l} 12 y+d=-19 y+t \\ y=\square \end{array}
  1. Identify the system: Identify the system of equations and the goal.\newlineWe have the system of equations:\newline11) 12y+d=19y+t12y + d = -19y + t\newline22) y=y = \square (we need to find the value of yy)
  2. Combine like terms: Combine like terms to isolate yy. Add 19y19y to both sides of the first equation to get yy terms on one side: \newline12y+19y+d=t12y + 19y + d = t\newline31y+d=t31y + d = t
  3. Isolate y: Isolate y by subtracting dd from both sides.\newline31y=td31y = t - d
  4. Divide both sides: Divide both sides by 3131 to solve for yy.\newliney=td31y = \frac{t - d}{31}

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