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Solve for 
x.
Assume the equation has a solution for 
x.

{:[-px+r=-8x-2],[x=◻]:}

Solve for x x .\newlineAssume the equation has a solution for x x .\newlinepx+r=8x2x= \begin{array}{l} -p x+r=-8 x-2 \\ x=\square \end{array}

Full solution

Q. Solve for x x .\newlineAssume the equation has a solution for x x .\newlinepx+r=8x2x= \begin{array}{l} -p x+r=-8 x-2 \\ x=\square \end{array}
  1. Identify System and Goal: Identify the given system of equations and the goal of solving for xx.\begin{align*}\{-p\cdot x+r&=-8\cdot x-2\},\[1ex] \{x&=\square\}:\end{align*}We need to find the value of xx that satisfies both equations.
  2. Combine Like Terms: Combine like terms in the first equation to isolate xx.
    px+r=8x2-p \cdot x + r = -8 \cdot x - 2
    Add pxp \cdot x to both sides to get all xx terms on one side.
    r=8x+px2r = -8 \cdot x + p \cdot x - 2
    r=x(8+p)2r = x \cdot (-8 + p) - 2
  3. Isolate x in the Equation: Isolate x in the equation.\newliner=x(8+p)2r = x(-8 + p) - 2\newlineAdd 22 to both sides.\newliner+2=x(8+p)r + 2 = x(-8 + p)\newlineDivide both sides by (8+p)(-8 + p) to solve for x.\newlinex=r+28+px = \frac{r + 2}{-8 + p}

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