Solve for x. Assume the equation has a solution for x. {:[d*(-3+x)=kx+9],[x=◻]:}

Simplify equation: First, let's simplify the first equation in the system: d*(-3+x) = kx + 9. We distribute d across the terms inside the parentheses: -3d + dx = kx + 9.Isolate x terms: Next, we want to isolate x terms on one side of the equation. To do this, we can add 3d to both sides: dx = kx + 9 + 3d.Subtract kx: Now, we need to get all the x terms on one side by subtracting kx from both sides: dx - kx = 9 + 3d.Factor out x: We can factor out x from the left side of the equation: x(d - k) = 9 + 3d.Solve for x: To solve for x, we divide both sides of the equation by (d - k), assuming d - k is not equal to zero: x = (9 + 3d) / (d - k).Final solution: Since the second part of the system of equations indicates that x equals a blank square, we can assume that the blank square is the solution we found: x = (9 + 3d) / (d - k).

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Solve for
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Assume the equation has a solution for
x.

{:[d*(-3+x)=kx+9],[x=◻]:}

Solve for $x$ . $\newline$ Assume the equation has a solution for $x$ . $\newline$ $\begin{array}{l} d \cdot(-3+x)=k x+9 \\ x=\square \end{array}$

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Algebra 1

Rearrange multi-variable equations

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Q. Solve for

x

\newline

Assume the equation has a solution for

x

\newline

\begin{array}{l} d \cdot(-3+x)=k x+9 \\ x=\square \end{array}

Simplify equation: First, let's simplify the first equation in the system: $d*(-3+x) = kx + 9$ . We distribute $d$ across the terms inside the parentheses: $-3d + dx = kx + 9$ .
Isolate $x$ terms: Next, we want to isolate $x$ terms on one side of the equation. To do this, we can add $3d$ to both sides: $dx = kx + 9 + 3d$ .
Subtract $kx$ : Now, we need to get all the $x$ terms on one side by subtracting $kx$ from both sides: $dx - kx = 9 + 3d$ .
Factor out $x$ : We can factor out $x$ from the left side of the equation: $x(d - k) = 9 + 3d$ .
Solve for x: To solve for x, we divide both sides of the equation by $(d - k)$ , assuming $d - k \neq 0$ : $x = \frac{9 + 3d}{d - k}$ .
Final solution: Since the second part of the system of equations indicates that $x$ equals a blank square, we can assume that the blank square is the solution we found: $x = \frac{9 + 3d}{d - k}$ .