Solve for x. Assume the equation has a solution for x. {:[ax+3x=bx+5],[x=◻]:}

Combine like terms: Combine like terms on the left side of the equation. ax + 3x can be combined because they are like terms (both have the variable x). (ax + 3x) = a*x + 3*x = (a + 3)x Now the equation looks like: (a + 3)x = bx + 5Subtract bx from both sides: Subtract bx from both sides to get all terms with x on one side. (a + 3)x - bx = bx + 5 - bx This simplifies to: (a + 3)x - bx = 5Combine like terms: Combine like terms on the left side of the equation. (a + 3)x - bx can be combined because they are like terms (both have the variable x). (a + 3 - b)x = 5 Now the equation looks like: (a + 3 - b)x = 5Divide both sides: Divide both sides by the coefficient of x, which is (a + 3 - b). x = 5 / (a + 3 - b) This gives us the value of x in terms of a and b.

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Solve for
x.
Assume the equation has a solution for
x.

{:[ax+3x=bx+5],[x=◻]:}

Solve for $x$ . $\newline$ Assume the equation has a solution for $x$ . $\newline$ $\begin{array}{l} a x+3 x=b x+5 \\ x=\square \end{array}$

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Math Problems

Algebra 1

Rearrange multi-variable equations

Full solution

Q. Solve for

x

\newline

Assume the equation has a solution for

x

\newline

\begin{array}{l} a x+3 x=b x+5 \\ x=\square \end{array}

Combine like terms: Combine like terms on the left side of the equation. $\newline$ $ax + 3x$ can be combined because they are like terms (both have the variable $x$ ). $\newline$ $(ax + 3x) = a \cdot x + 3 \cdot x = (a + 3)x$ $\newline$ Now the equation looks like: $(a + 3)x = bx + 5$
Subtract $bx$ from both sides: Subtract $bx$ from both sides to get all terms with $x$ on one side. $\newline$ $(a + 3)x - bx = bx + 5 - bx$ $\newline$ This simplifies to: $(a + 3)x - bx = 5$
Combine like terms: Combine like terms on the left side of the equation. $\newline$ $(a + 3)x - bx$ can be combined because they are like terms (both have the variable $x$ ). $\newline$ $(a + 3 - b)x = 5$ $\newline$ Now the equation looks like: $(a + 3 - b)x = 5$
Divide both sides: Divide both sides by the coefficient of $x$ , which is $(a + 3 - b)$ . $\newline$ $x = \frac{5}{(a + 3 - b)}$ $\newline$ This gives us the value of $x$ in terms of $a$ and $b$ .