Solve for t. {:[2-16 t=6(-3t+2)],[t=]:}

Simplify the equation using distributive property: First, let's simplify the equation 6(-3t + 2) using the distributive property. 6(-3t + 2) = 6(-3t) + 6(2) = -18t + 12Isolate the variable t: Now we have the simplified equation: 2 - 16t = -18t + 12. Next, we will isolate the variable t by adding 18t to both sides of the equation. 2 - 16t + 18t = -18t + 12 + 18t 2 + 2t = 12Subtract to isolate the term with t: Subtract 2 from both sides to isolate the term with t. 2 + 2t - 2 = 12 - 2 2t = 10Divide to solve for t: Divide both sides by 2 to solve for t. 2t / 2 = 10 / 2 t = 5

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Solve for
t.

{:[2-16 t=6(-3t+2)],[t=]:}

Solve for $t$ . $\newline$ $\begin{array}{l} 2-16 t=6(-3 t+2) \\ t=\square \end{array}$

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Algebra 1

Solve multi-step linear equations

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Q. Solve for

t

\newline

\begin{array}{l} 2-16 t=6(-3 t+2) \\ t=\square \end{array}

Simplify the equation using distributive property: First, let's simplify the equation $6(-3t + 2)$ using the distributive property. $6(-3t + 2) = 6(-3t) + 6(2) = -18t + 12$
Isolate the variable $t$ : Now we have the simplified equation: $2$ - $16$ t = $-18$ t + $12$ . $\newline$ Next, we will isolate the variable $t$ by adding $18$ t to both sides of the equation. $\newline$ $2$ - $16$ t + $18$ t = $-18$ t + $12$ + $18$ t $\newline$ $2$ + $2$ t = $12$
Subtract to isolate the term with $t$ : Subtract $2$ from both sides to isolate the term with $t$ . $\newline$ $2$ + $2$ t - $2$ = $12$ - $2$ $\newline$ $2$ t = $10$
Divide to solve for t: Divide both sides by $2$ to solve for t. $\newline$ $\frac{2t}{2} = \frac{10}{2}$ $\newline$ $t = 5$