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Let’s check out your problem:
Solve for
t
t
t
.
\newline
16
−
2
t
=
t
+
9
+
4
t
t
=
□
\begin{array}{l} 16-2 t=t+9+4 t \\ t=\square \end{array}
16
−
2
t
=
t
+
9
+
4
t
t
=
□
View step-by-step help
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Math Problems
Algebra 1
Solve linear equations with variables on both sides
Full solution
Q.
Solve for
t
t
t
.
\newline
16
−
2
t
=
t
+
9
+
4
t
t
=
□
\begin{array}{l} 16-2 t=t+9+4 t \\ t=\square \end{array}
16
−
2
t
=
t
+
9
+
4
t
t
=
□
Write down the equation:
Write down the given
system of equations
.
\newline
We have the equation
16
−
2
t
=
t
+
9
+
4
t
16 - 2t = t + 9 + 4t
16
−
2
t
=
t
+
9
+
4
t
.
Combine like terms:
Combine like terms on the right side of the equation.
\newline
16
−
2
t
=
t
+
9
+
4
t
16 - 2t = t + 9 + 4t
16
−
2
t
=
t
+
9
+
4
t
\newline
16
−
2
t
=
5
t
+
9
16 - 2t = 5t + 9
16
−
2
t
=
5
t
+
9
Move terms to each side:
Move all terms containing
t
t
t
to one side and constant terms to the other side.
16
−
2
t
−
5
t
=
5
t
+
9
−
5
t
16 - 2t - 5t = 5t + 9 - 5t
16
−
2
t
−
5
t
=
5
t
+
9
−
5
t
16
−
7
t
=
9
16 - 7t = 9
16
−
7
t
=
9
Isolate the term with
t
:
Subtract
16
16
16
from both sides to isolate the term with
t
.
\newline
16
16
16
-
7
7
7
t -
16
16
16
=
9
9
9
-
16
16
16
\newline
−
7
-7
−
7
t =
−
7
-7
−
7
Solve for t:
Divide both sides by
−
7
-7
−
7
to solve for
t
t
t
.
−
7
t
−
7
=
−
7
−
7
\frac{-7t}{-7} = \frac{-7}{-7}
−
7
−
7
t
=
−
7
−
7
t
=
1
t = 1
t
=
1
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(B) Exactly one solution
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9
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9
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x
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6
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9
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108
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Choose
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x
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4
x
−
2
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−
6
(
x
+
7
)
=
−
4
x
−
2
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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How many solutions does the following equation have?
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4
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x
\newline
Choose
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\newline
(A) No solutions
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(B) Exactly one solution
\newline
(C) Infinitely many solutions
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Question
How many solutions does the following equation have?
\newline
−
17
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17
y
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17
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−
2
)
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17
y
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\newline
Choose
1
1
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answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
9
z
−
6
+
7
z
=
16
z
−
6
9z-6+7z=16z-6
9
z
−
6
+
7
z
=
16
z
−
6
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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