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Let’s check out your problem:
Solve for
s
s
s
.
\newline
2
s
+
4
=
5
(
−
4
−
2
s
)
s
=
□
\begin{array}{l} 2 s+4=5(-4-2 s) \\ s=\square \end{array}
2
s
+
4
=
5
(
−
4
−
2
s
)
s
=
□
View step-by-step help
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Math Problems
Algebra 1
Solve multi-step linear equations
Full solution
Q.
Solve for
s
s
s
.
\newline
2
s
+
4
=
5
(
−
4
−
2
s
)
s
=
□
\begin{array}{l} 2 s+4=5(-4-2 s) \\ s=\square \end{array}
2
s
+
4
=
5
(
−
4
−
2
s
)
s
=
□
Apply distributive property:
Apply the
distributive property
to the right side of the equation.
\newline
5
(
−
4
−
2
s
)
5(-4 - 2s)
5
(
−
4
−
2
s
)
\newline
=
5
(
−
4
)
+
5
(
−
2
s
)
5(-4) + 5(-2s)
5
(
−
4
)
+
5
(
−
2
s
)
\newline
=
−
20
−
10
s
-20 - 10s
−
20
−
10
s
Rewrite equation with simplified right side:
Rewrite the equation with the simplified right side.
2
s
+
4
=
−
20
−
10
s
2s + 4 = -20 - 10s
2
s
+
4
=
−
20
−
10
s
Add
s
s
s
terms to one side:
Add
10
s
10s
10
s
to both sides to get all the
s
s
s
terms on one side.
\newline
2
s
+
10
s
+
4
=
−
20
−
10
s
+
10
s
2s + 10s + 4 = -20 - 10s + 10s
2
s
+
10
s
+
4
=
−
20
−
10
s
+
10
s
\newline
12
s
+
4
=
−
20
12s + 4 = -20
12
s
+
4
=
−
20
Isolate term with
s
s
s
:
Subtract
4
4
4
from both sides to isolate the term with
s
s
s
.
12
s
+
4
−
4
=
−
20
−
4
12s + 4 - 4 = -20 - 4
12
s
+
4
−
4
=
−
20
−
4
12
s
=
−
24
12s = -24
12
s
=
−
24
Divide both sides to solve for
s
:
Divide both sides by
12
12
12
to solve for
s
.
\newline
12
12
12
s /
12
12
12
=
−
24
-24
−
24
/
12
12
12
\newline
s =
−
2
-2
−
2
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(B) Exactly one solution
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6
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(C) Infinitely many solutions
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\newline
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\newline
(A) No solutions
\newline
(B) Exactly one solution
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(C) Infinitely many solutions
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Question
How many solutions does the following equation have?
\newline
9
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=
16
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−
6
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\newline
Choose
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\newline
(A) No solutions
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