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Solve for 
r.
Give an exact answer.

{:[(1)/(2)r-3=3(4-(3)/(2)r)],[r=◻]:}

Solve for r r .\newlineGive an exact answer.\newline12r3=3(432r) \frac{1}{2} r-3=3\left(4-\frac{3}{2} r\right) \newliner= r=

Full solution

Q. Solve for r r .\newlineGive an exact answer.\newline12r3=3(432r) \frac{1}{2} r-3=3\left(4-\frac{3}{2} r\right) \newliner= r=
  1. Distribute the 33: Distribute the 33 on the right side of the equation to both terms inside the parentheses.3(4(32)r)3(4 - \left(\frac{3}{2}\right)r) =3×43×(32)r= 3 \times 4 - 3 \times \left(\frac{3}{2}\right)r =12(92)r= 12 - \left(\frac{9}{2}\right)r
  2. Rewrite the equation: Rewrite the equation with the distributed terms. (12)r3=12(92)r(\frac{1}{2})r - 3 = 12 - (\frac{9}{2})r
  3. Add (92)r(\frac{9}{2})r to both sides: Add (92)r(\frac{9}{2})r to both sides of the equation to get all rr terms on one side.\newline(12)r+(92)r=12(92)r+(92)r(\frac{1}{2})r + (\frac{9}{2})r = 12 - (\frac{9}{2})r + (\frac{9}{2})r\newline(12+92)r=12(\frac{1}{2} + \frac{9}{2})r = 12\newline(102)r=12(\frac{10}{2})r = 12\newline5r=125r = 12
  4. Divide both sides by 55: Divide both sides of the equation by 55 to solve for rr.5r5=125\frac{5r}{5} = \frac{12}{5}r=125r = \frac{12}{5}

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