Solve for r. {:[4r-3=3(3r+4)],[r=◻]:}

Apply distributive property: Apply the distributive property to the right side of the equation. 4r - 3 = 3(3r + 4) = 3 * 3r + 3 * 4 = 9r + 12Expand the right side: Rewrite the equation with the expanded right side. 4r - 3 = 9r + 12Rearrange terms: Get all terms with r on one side and constant terms on the other side by subtracting 9r from both sides. 4r - 9r - 3 = 9r - 9r + 12 -5r - 3 = 12Isolate the term with r: Isolate the term with r by adding 3 to both sides of the equation. -5r - 3 + 3 = 12 + 3 -5r = 15Solve for r: Solve for r by dividing both sides by -5. -5r / -5 = 15 / -5 r = -3

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Solve for $r$ . $\newline$ $\begin{array}{l} 4 r-3=3(3 r+4) \\ r=\square \end{array}$

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Algebra 1

Solve multi-step linear equations

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Q. Solve for

r

\newline

\begin{array}{l} 4 r-3=3(3 r+4) \\ r=\square \end{array}

Apply distributive property: Apply the distributive property to the right side of the equation. $\newline$ $4r - 3 = 3(3r + 4)$ $\newline$ $= 3 \times 3r + 3 \times 4$ $\newline$ $= 9r + 12$
Expand the right side: Rewrite the equation with the expanded right side. $\newline$ $4r - 3 = 9r + 12$
Rearrange terms: Get all terms with $r$ on one side and constant terms on the other side by subtracting $9r$ from both sides. $\newline$ $4r - 9r - 3 = 9r - 9r + 12$ $\newline$ $-5r - 3 = 12$
Isolate the term with $r$ : Isolate the term with $r$ by adding $3$ to both sides of the equation. $\newline$ $-5$ r - $3$ + $3$ = $12$ + $3$ $\newline$ $-5$ r = $15$
Solve for r: Solve for r by dividing both sides by \(-5＂). $\newline$ $-5r / -5 = 15 / -5$ $\newline$ $r = -3$