Solve for r. {:[16-2r=-3r+6r+1],[r=◻]:}

Write down the equations: Write down the given system of equations. {:[16 - 2r = -3r + 6r + 1],[r = ◻]:}Simplify the equation: Simplify the equation on the right side by combining like terms. 16 - 2r = (-3r + 6r) + 1 16 - 2r = 3r + 1Rearrange the equation: Move all terms containing r to one side and constant terms to the other side. 16 - 2r - 3r = 1 16 - 5r = 1Isolate the variable: Isolate the variable r by moving the constant term to the other side. -5r = 1 - 16 -5r = -15Solve for r: Solve for r by dividing both sides by -5. r = (-15) / (-5) r = 3

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Solve for
r.

{:[16-2r=-3r+6r+1],[r=◻]:}

Solve for $r$ . $\newline$ $\begin{array}{l} 16-2 r=-3 r+6 r+1 \\ r=\square \end{array}$

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Math Problems

Algebra 1

Solve linear equations with variables on both sides

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Q. Solve for

r

\newline

\begin{array}{l} 16-2 r=-3 r+6 r+1 \\ r=\square \end{array}

Write down the equations: Write down the given system of equations. $\begin{cases} 16 - 2r = -3r + 6r + 1 \ r = \square \end{cases}$
Simplify the equation: Simplify the equation on the right side by combining like terms. $\newline$ $16 - 2r = (-3r + 6r) + 1$ $\newline$ $16 - 2r = 3r + 1$
Rearrange the equation: Move all terms containing $r$ to one side and constant terms to the other side. $16 - 2r - 3r = 1$ $16 - 5r = 1$
Isolate the variable: Isolate the variable $r$ by moving the constant term to the other side. $-5r = 1 - 16$ $-5r = -15$
Solve for $r$ : Solve for $r$ by dividing both sides by $-5$ . $\newline$ $r = \frac{{-15}}{{-5}}$ $\newline$ $r = 3$