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Solve for 
p.

10 p-3=2(12+4p)-7

p=

Solve for p p .\newline10p3=2(12+4p)7p= \begin{array}{l} 10 p-3=2(12+4 p)-7 \\ p=\square \end{array}

Full solution

Q. Solve for p p .\newline10p3=2(12+4p)7p= \begin{array}{l} 10 p-3=2(12+4 p)-7 \\ p=\square \end{array}
  1. Distribute the 22: First, we need to distribute the 22 into the parentheses on the right side of the equation.\newline2(12+4p)=2×12+2×4p2(12 + 4p) = 2 \times 12 + 2 \times 4p\newline=24+8p= 24 + 8p
  2. Rewrite the equation: Now, we rewrite the equation with the distributed terms. 10p3=24+8p710p - 3 = 24 + 8p - 7
  3. Simplify the right side: Next, we simplify the right side of the equation by combining like terms (2424 and 7-7).\newline10p3=247+8p10p - 3 = 24 - 7 + 8p\newline10p3=17+8p10p - 3 = 17 + 8p
  4. Isolate the variable p p : We then isolate the variable p p by moving all terms with p p to one side and constants to the other side. We can subtract 8p 8p from both sides to move the p p terms to the left.\newline10p8p3=17+8p8p 10p - 8p - 3 = 17 + 8p - 8p \newline2p3=17 2p - 3 = 17
  5. Add 33 to both sides: Now, we add 33 to both sides to isolate the term with pp.\newline2p3+3=17+32p - 3 + 3 = 17 + 3\newline2p=202p = 20
  6. Divide both sides by 22: Finally, we divide both sides by 22 to solve for pp.2p2=202\frac{2p}{2} = \frac{20}{2}p=10p = 10

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