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Solve for h. {:[17+4h+2=1-5h],[h=]:}

Solve for h h .\newline17+4h+2=1−5hh=□ \begin{array}{l} 17+4 h+2=1-5 h \\ h=\square \end{array}

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Full solution

Q. Solve for h h .\newline17+4h+2=1−5hh=□ \begin{array}{l} 17+4 h+2=1-5 h \\ h=\square \end{array}
  1. Combine like terms: Combine like terms in the first equation.\newline17+4h+2=1−5h17 + 4h + 2 = 1 - 5h\newline19+4h=1−5h19 + 4h = 1 - 5h
  2. Move h terms to one side: Move all the h terms to one side of the equation by adding 5h5h to both sides.\newline19+4h+5h=1−5h+5h19 + 4h + 5h = 1 - 5h + 5h\newline19+9h=119 + 9h = 1
  3. Subtract 1919 to isolate h: Subtract 1919 from both sides to isolate the h term.\newline19+9h−19=1−1919 + 9h - 19 = 1 - 19\newline9h=−189h = -18
  4. Divide both sides by 99: Divide both sides by 99 to solve for hh.9h9=−189\frac{9h}{9} = \frac{-18}{9}h=−2h = -2

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