Solve for h. {:[15.3+1h=1.3-1h],[h=◻]:}

Write down the system: Write down the given system of equations. We have the system of equations: 15.3 + 1h = 1.3 - 1h We need to solve for h.Combine like terms: Combine like terms by moving the variable h to one side of the equation. To do this, we add 1h to both sides of the equation to get h on one side: 15.3 + 1h + 1h = 1.3 - 1h + 1h This simplifies to: 15.3 + 2h = 1.3Isolate the variable: Isolate the variable h by moving the constant term to the other side of the equation. To do this, we subtract 15.3 from both sides of the equation: 15.3 + 2h - 15.3 = 1.3 - 15.3 This simplifies to: 2h = -14Solve for h: Solve for h by dividing both sides of the equation by the coefficient of h. To find h, we divide both sides by 2: 2h / 2 = -14 / 2 This simplifies to: h = -7

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Solve for
h.

{:[15.3+1h=1.3-1h],[h=◻]:}

Solve for $h$ . $\newline$ $\begin{array}{l} 15.3+1 h=1.3-1 h \\ h=\square \end{array}$

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Math Problems

Algebra 1

Solve linear equations with variables on both sides

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Q. Solve for

h

\newline

\begin{array}{l} 15.3+1 h=1.3-1 h \\ h=\square \end{array}

Write down the system: Write down the given system of equations. $\newline$ We have the system of equations: $\newline$ $15.3 + 1h = 1.3 - 1h$ $\newline$ We need to solve for $h$ .
Combine like terms: Combine like terms by moving the variable $h$ to one side of the equation. $\newline$ To do this, we add $1h$ to both sides of the equation to get $h$ on one side: $\newline$ $15.3 + 1h + 1h = 1.3 - 1h + 1h$ $\newline$ This simplifies to: $\newline$ $15.3 + 2h = 1.3$
Isolate the variable: Isolate the variable $h$ by moving the constant term to the other side of the equation. $\newline$ To do this, we subtract $15.3$ from both sides of the equation: $\newline$ $15.3 + 2h - 15.3 = 1.3 - 15.3$ $\newline$ This simplifies to: $\newline$ $2h = -14$
Solve for h: Solve for h by dividing both sides of the equation by the coefficient of h. $\newline$ To find h, we divide both sides by $2$ : $\newline$ $\frac{2h}{2} = \frac{-14}{2}$ $\newline$ This simplifies to: $\newline$ $h = -7$