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Solve for 
f.

{:[2+1.25 f=10-2.75 f],[f=◻]:}

Solve for f f .\newline2+1.25f=102.75ff= \begin{array}{l} 2+1.25 f=10-2.75 f \\ f=\square \end{array}

Full solution

Q. Solve for f f .\newline2+1.25f=102.75ff= \begin{array}{l} 2+1.25 f=10-2.75 f \\ f=\square \end{array}
  1. Given equation: Start with the given equation.\newline2+1.25f=102.75f2 + 1.25f = 10 - 2.75f\newlineWe want to collect all the ff terms on one side and the constant terms on the other side.
  2. Move f terms to the left side: Add 2.75f2.75f to both sides to move the f terms to the left side.\newline2+1.25f+2.75f=102.75f+2.75f2 + 1.25f + 2.75f = 10 - 2.75f + 2.75f\newlineThis simplifies to:\newline2+4f=102 + 4f = 10
  3. Isolate the term with ff: Subtract 22 from both sides to isolate the term with ff.
    2+4f2=1022 + 4f - 2 = 10 - 2
    This simplifies to:
    4f=84f = 8
  4. Solve for f: Divide both sides by 44 to solve for f.\newline4f4=84\frac{4f}{4} = \frac{8}{4}\newlineThis simplifies to:\newlinef=2f = 2

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