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Let’s check out your problem:
Solve for
e
e
e
.
\newline
7
(
2
e
−
1
)
−
3
=
6
+
6
e
e
=
□
\begin{array}{l} 7(2 e-1)-3=6+6 e \\ e=\square \end{array}
7
(
2
e
−
1
)
−
3
=
6
+
6
e
e
=
□
View step-by-step help
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Math Problems
Algebra 1
Solve multi-step linear equations
Full solution
Q.
Solve for
e
e
e
.
\newline
7
(
2
e
−
1
)
−
3
=
6
+
6
e
e
=
□
\begin{array}{l} 7(2 e-1)-3=6+6 e \\ e=\square \end{array}
7
(
2
e
−
1
)
−
3
=
6
+
6
e
e
=
□
Simplify expression using distributive property:
Simplify the expression
7
(
2
e
−
1
)
7(2e-1)
7
(
2
e
−
1
)
by using the
distributive property
.
\newline
7
(
2
e
−
1
)
=
7
×
2
e
+
7
×
(
−
1
)
7(2e-1) = 7 \times 2e + 7 \times (-1)
7
(
2
e
−
1
)
=
7
×
2
e
+
7
×
(
−
1
)
\newline
=
14
e
−
7
= 14e - 7
=
14
e
−
7
Combine like terms and substitute into equation:
Substitute the simplified expression into the equation and combine like terms.
\newline
14
e
−
7
−
3
=
6
+
6
e
14e - 7 - 3 = 6 + 6e
14
e
−
7
−
3
=
6
+
6
e
\newline
14
e
−
10
=
6
+
6
e
14e - 10 = 6 + 6e
14
e
−
10
=
6
+
6
e
Isolate terms with e on one side of equation:
Isolate the terms with
e
e
e
on one side of the equation.
14
e
−
6
e
=
6
+
10
14e - 6e = 6 + 10
14
e
−
6
e
=
6
+
10
8
e
=
16
8e = 16
8
e
=
16
Divide both sides by
8
8
8
to solve for e:
Divide both sides of the equation by
8
8
8
to solve for e.
\newline
8
e
8
=
16
8
\frac{8e}{8} = \frac{16}{8}
8
8
e
=
8
16
\newline
e
=
2
e = 2
e
=
2
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(A) No solutions
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−
6
(
x
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7
)
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4
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−
2
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1
1
answer:
\newline
(A) No solutions
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(B) Exactly one solution
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1
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(A) No solutions
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(B) Exactly one solution
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(C) Infinitely many solutions
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Question
How many solutions does the following equation have?
\newline
9
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z
=
16
z
−
6
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z
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6
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\newline
Choose
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\newline
(A) No solutions
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(B) Exactly one solution
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