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Let’s check out your problem:
Solve for
c
c
c
.
\newline
Give an exact answer.
\newline
0.2
(
10
−
5
c
)
=
5
c
−
16
0.2(10-5 c)=5 c-16
0.2
(
10
−
5
c
)
=
5
c
−
16
\newline
c
=
c=
c
=
View step-by-step help
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Math Problems
Algebra 1
Solve multi-step linear equations
Full solution
Q.
Solve for
c
c
c
.
\newline
Give an exact answer.
\newline
0.2
(
10
−
5
c
)
=
5
c
−
16
0.2(10-5 c)=5 c-16
0.2
(
10
−
5
c
)
=
5
c
−
16
\newline
c
=
c=
c
=
Distribute
0
0
0
.
2
2
2
:
Distribute
0.2
0.2
0.2
to the terms inside the parentheses.
\newline
0.2
(
10
−
5
c
)
=
0.2
×
10
−
0.2
×
5
c
0.2(10 - 5c) = 0.2 \times 10 - 0.2 \times 5c
0.2
(
10
−
5
c
)
=
0.2
×
10
−
0.2
×
5
c
\newline
=
2
−
c
= 2 - c
=
2
−
c
Rewrite equation:
Rewrite the equation after distribution.
2
−
c
=
5
c
−
16
2 - c = 5c - 16
2
−
c
=
5
c
−
16
Add
c
c
c
terms:
Add
c
c
c
to both sides to bring all the
c
c
c
terms to one side.
\newline
2
−
c
+
c
=
5
c
−
16
+
c
2 - c + c = 5c - 16 + c
2
−
c
+
c
=
5
c
−
16
+
c
\newline
2
=
6
c
−
16
2 = 6c - 16
2
=
6
c
−
16
Isolate c term:
Add
16
16
16
to both sides to isolate the term with
c
c
c
.
\newline
2
+
16
=
6
c
−
16
+
16
2 + 16 = 6c - 16 + 16
2
+
16
=
6
c
−
16
+
16
\newline
18
=
6
c
18 = 6c
18
=
6
c
Solve for c:
Divide both sides by
6
6
6
to solve for c.
\newline
18
6
=
6
c
6
\frac{18}{6} = \frac{6c}{6}
6
18
=
6
6
c
\newline
3
=
c
3 = c
3
=
c
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(A) No solutions
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(B) Exactly one solution
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9
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x
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−
6
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x
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7
)
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4
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−
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\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
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(B) Exactly one solution
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(C) Infinitely many solutions
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\newline
Choose
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\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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Question
How many solutions does the following equation have?
\newline
9
z
−
6
+
7
z
=
16
z
−
6
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9
z
−
6
+
7
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=
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−
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\newline
Choose
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answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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