Solve for c. (8)/(3)c-2=(2)/(3)c-12 c=

Identify like terms: Write down the equation and identify like terms. (8/3)c - 2 = (2/3)c - 12 We have terms with c on both sides of the equation and constant terms on both sides as well.Eliminate the fraction: Eliminate the fraction by multiplying every term by the common denominator, which is 3. 3 * ((8/3)c - 2) = 3 * ((2/3)c - 12) This gives us: 8c - 6 = 2c - 36Move terms with c: Move the terms with c to one side of the equation by subtracting 2c from both sides. 8c - 2c - 6 = 2c - 2c - 36 This simplifies to: 6c - 6 = -36Move constant term: Move the constant term to the other side by adding 6 to both sides. 6c - 6 + 6 = -36 + 6 This simplifies to: 6c = -30Divide both sides: Divide both sides by 6 to solve for c. 6c / 6 = -30 / 6 This gives us: c = -5

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Solve for
c.

(8)/(3)c-2=(2)/(3)c-12

c=

Solve for $c$ . $\newline$ $\begin{array}{l} \frac{8}{3} c-2=\frac{2}{3} c-12 \\ c=\square \end{array}$

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Math Problems

Algebra 1

Solve linear equations with variables on both sides

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Q. Solve for

c

\newline

\begin{array}{l} \frac{8}{3} c-2=\frac{2}{3} c-12 \\ c=\square \end{array}

Identify like terms: Write down the equation and identify like terms. $\newline$ $(\frac{8}{3})c - 2 = (\frac{2}{3})c - 12$ $\newline$ We have terms with $c$ on both sides of the equation and constant terms on both sides as well.
Eliminate the fraction: Eliminate the fraction by multiplying every term by the common denominator, which is $3$ . $\newline$ $3 \times \left(\frac{8}{3}c - 2\right) = 3 \times \left(\frac{2}{3}c - 12\right)$ $\newline$ This gives us: $\newline$ $8c - 6 = 2c - 36$
Move terms with $c$ : Move the terms with $c$ to one side of the equation by subtracting $2$ c from both sides. $\newline$ $8$ c - $2$ c - $6$ = $2$ c - $2$ c - $36$ $\newline$ This simplifies to: $\newline$ $6$ c - $6$ = $-36$
Move constant term: Move the constant term to the other side by adding $6$ to both sides. $\newline$ $6c - 6 + 6 = -36 + 6$ $\newline$ This simplifies to: $\newline$ $6c = -30$
Divide both sides: Divide both sides by $6$ to solve for $c$ . $\newline$ $\frac{6c}{6} = \frac{-30}{6}$ $\newline$ This gives us: $\newline$ $c = -5$