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Let’s check out your problem:
Solve for
c
c
c
.
\newline
6
c
+
14
=
−
5
c
+
4
+
9
c
c
=
\begin{array}{l} 6 c+14=-5 c+4+9 c \\ c= \end{array}
6
c
+
14
=
−
5
c
+
4
+
9
c
c
=
View step-by-step help
Home
Math Problems
Algebra 1
Solve linear equations with variables on both sides
Full solution
Q.
Solve for
c
c
c
.
\newline
6
c
+
14
=
−
5
c
+
4
+
9
c
c
=
\begin{array}{l} 6 c+14=-5 c+4+9 c \\ c= \end{array}
6
c
+
14
=
−
5
c
+
4
+
9
c
c
=
Write equation:
Write down the given equation.
6
c
+
14
=
−
5
c
+
4
+
9
c
6c + 14 = -5c + 4 + 9c
6
c
+
14
=
−
5
c
+
4
+
9
c
Combine like terms:
Combine like terms on the right side of the equation.
\newline
6
c
+
14
=
(
9
c
−
5
c
)
+
4
6c + 14 = (9c - 5c) + 4
6
c
+
14
=
(
9
c
−
5
c
)
+
4
\newline
6
c
+
14
=
4
c
+
4
6c + 14 = 4c + 4
6
c
+
14
=
4
c
+
4
Move terms and constants:
Move all terms containing
c
c
c
to one side of the equation and constant terms to the other side.
\newline
6
c
−
4
c
=
4
−
14
6c - 4c = 4 - 14
6
c
−
4
c
=
4
−
14
\newline
2
c
=
−
10
2c = -10
2
c
=
−
10
Divide to solve for c:
Divide both sides of the equation by
2
2
2
to solve for
c
c
c
.
\newline
2
c
2
=
−
10
2
\frac{2c}{2} = \frac{-10}{2}
2
2
c
=
2
−
10
\newline
c
=
−
5
c = -5
c
=
−
5
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−
6
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x
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7
)
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−
4
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\newline
Choose
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1
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answer:
\newline
(A) No solutions
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(B) Exactly one solution
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(C) Infinitely many solutions
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\newline
(A) No solutions
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(B) Exactly one solution
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(C) Infinitely many solutions
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Question
How many solutions does the following equation have?
\newline
9
z
−
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+
7
z
=
16
z
−
6
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9
z
−
6
+
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=
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−
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\newline
Choose
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\newline
(A) No solutions
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(B) Exactly one solution
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