Solve for c. 4(3+c)+c=c+4 c=

Distribute the 4: Distribute the 4 into the parentheses. 4(3+c) + c = c + 4 4*3 + 4*c + c = c + 4 12 + 4c + c = c + 4Combine like terms: Combine like terms on the left side of the equation. 12 + 4c + c = c + 4 12 + 5c = c + 4Subtract c from both sides: Subtract c from both sides to get all the c terms on one side. 12 + 5c - c = c + 4 - c 12 + 4c = 4Subtract 12 from both sides: Subtract 12 from both sides to isolate the c term. 12 + 4c - 12 = 4 - 12 4c = -8Divide both sides by 4: Divide both sides by 4 to solve for c. 4c / 4 = -8 / 4 c = -2

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Solve for $c$ . $\newline$ $4(3+c)+c=c+4$ $\newline$ $c=$

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Algebra 1

Solve multi-step linear equations

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Q. Solve for

c

\newline

4(3+c)+c=c+4

\newline

c=

Distribute the $4$ : Distribute the $4$ into the parentheses. $\newline$ $4(3+c) + c = c + 4$ $\newline$ $4\cdot 3 + 4c + c = c + 4$ $\newline$ $12 + 4c + c = c + 4$
Combine like terms: Combine like terms on the left side of the equation. $\newline$ $12 + 4c + c = c + 4$ $\newline$ $12 + 5c = c + 4$
Subtract $c$ from both sides: Subtract $c$ from both sides to get all the $c$ terms on one side. $\newline$ $12 + 5c - c = c + 4 - c$ $\newline$ $12 + 4c = 4$
Subtract $12$ from both sides: Subtract $12$ from both sides to isolate the c term. $\newline$ $12 + 4c - 12 = 4 - 12$ $\newline$ $4c = -8$
Divide both sides by $4$ : Divide both sides by $4$ to solve for $c$ . $\frac{4c}{4} = \frac{-8}{4}$ $c = -2$