Solve for c. 12 c-4=14 c-10 c=

Start with the equation: Start with the equation 12c - 4 = 14c - 10. To isolate the variable c, we need to get all the c terms on one side and the constant terms on the other side.Subtract 12c from both sides: Subtract 12c from both sides to move the c terms to one side. 12c - 4 - 12c = 14c - 10 - 12c This simplifies to: -4 = 2c - 10Add 10 to both sides: Add 10 to both sides to move the constant terms to the other side. -4 + 10 = 2c - 10 + 10 This simplifies to: 6 = 2cDivide both sides by 2: Divide both sides by 2 to solve for c. 6 / 2 = 2c / 2 This simplifies to: 3 = c

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Solve for $c$ . $\newline$ $12 c-4=14 c-10$ $\newline$ $c=$

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Algebra 1

Solve linear equations with variables on both sides

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Q. Solve for

c

\newline

12 c-4=14 c-10

\newline

c=

Start with the equation: Start with the equation $12c - 4 = 14c - 10$ . $\newline$ To isolate the variable $c$ , we need to get all the $c$ terms on one side and the constant terms on the other side.
Subtract $12$ c from both sides: Subtract $12c$ from both sides to move the $c$ terms to one side. $\newline$ $12c - 4 - 12c = 14c - 10 - 12c$ $\newline$ This simplifies to: $\newline$ $-4 = 2c - 10$
Add $10$ to both sides: Add $10$ to both sides to move the constant terms to the other side. $\newline$ $-4 + 10 = 2c - 10 + 10$ $\newline$ This simplifies to: $\newline$ $6 = 2c$
Divide both sides by $2$ : Divide both sides by $2$ to solve for $c$ . $\frac{6}{2} = \frac{2c}{2}$ This simplifies to: $3 = c$