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Solve for 
b.

{:[3-2(b-2)=2-7b],[b=]:}

Solve for b b .\newline32(b2)=27bb= \begin{array}{l} 3-2(b-2)=2-7 b \\ b=\square \end{array}

Full solution

Q. Solve for b b .\newline32(b2)=27bb= \begin{array}{l} 3-2(b-2)=2-7 b \\ b=\square \end{array}
  1. Simplify equation using distributive property: Simplify the equation 32(b2)3 - 2(b - 2) by using the distributive property.\newline32(b2)3 - 2(b - 2)\newline=32b+4= 3 - 2b + 4\newline=72b= 7 - 2b
  2. Isolate variable b by moving terms: Now we have the simplified equation 72b=27b7 - 2b = 2 - 7b. Next, we will isolate the variable b by moving all the b terms to one side and the constants to the other side.\newlineAdd 2b2b to both sides:\newline72b+2b=27b+2b7 - 2b + 2b = 2 - 7b + 2b\newline7=25b7 = 2 - 5b
  3. Add 5b5b to both sides: Now, add 5b5b to both sides to isolate the bb term on one side:\newline7+5b=25b+5b7 + 5b = 2 - 5b + 5b\newline7+5b=27 + 5b = 2
  4. Subtract 22 from both sides: Subtract 22 from both sides to solve for b:\newline7+5b2=227 + 5b - 2 = 2 - 2\newline5b+5=05b + 5 = 0

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