Solve for a. {:[a-15=4a-3],[a=◻]:}

Write down the equation: Write down the given system of equations. We have the equation a - 15 = 4a - 3.Isolate the variable a: Isolate the variable a on one side of the equation. To do this, we will subtract a from both sides of the equation to move all the a terms to one side. a - 15 - a = 4a - 3 - a This simplifies to: -15 = 3a - 3Add 3 to both sides: Add 3 to both sides of the equation to isolate the term with the variable a. -15 + 3 = 3a - 3 + 3 This simplifies to: -12 = 3aDivide both sides by 3: Divide both sides of the equation by 3 to solve for a. -12 / 3 = 3a / 3 This simplifies to: a = -4

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Solve for $a$ . $\newline$ $\begin{array}{l} a-15=4 a-3 \\ a=\square \end{array}$

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Algebra 1

Solve linear equations with variables on both sides

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Q. Solve for

a

\newline

\begin{array}{l} a-15=4 a-3 \\ a=\square \end{array}

Write down the equation: Write down the given system of equations. $\newline$ We have the equation $a - 15 = 4a - 3$ .
Isolate the variable $a$ : Isolate the variable $a$ on one side of the equation. $\newline$ To do this, we will subtract $a$ from both sides of the equation to move all the $a$ terms to one side. $\newline$ $a -$ $15$ - a = $4$ a - $3$ - a $\newline$ This simplifies to: $\newline$ $-15$ = $3$ a - $3$
Add $3$ to both sides: Add $3$ to both sides of the equation to isolate the term with the variable $a$ . $\newline$ $-15 + 3 = 3a - 3 + 3$ $\newline$ This simplifies to: $\newline$ $-12 = 3a$
Divide both sides by $3$ : Divide both sides of the equation by $3$ to solve for $a$ . $\frac{-12}{3} = \frac{3a}{3}$ This simplifies to: $a = -4$