Jude factored 28x2 as (14x)(2x2).Yasmin factored 28x2 as (7x)(4x).Which of them factored 28x2 correctly?Choose 1 answer:(A) Only Jude(B) Only Yasmin(C) Both Jude and Yasmin(D) Neither Jude nor Yasmin
Q. Jude factored 28x2 as (14x)(2x2).Yasmin factored 28x2 as (7x)(4x).Which of them factored 28x2 correctly?Choose 1 answer:(A) Only Jude(B) Only Yasmin(C) Both Jude and Yasmin(D) Neither Jude nor Yasmin
Examine Jude's Factorization: Let's examine Jude's factorization of 28x2:Jude factored 28x2 as (14x)(2x). To check if this is correct, we multiply the factors together:(14x)×(2x)=28x2.This is the original expression, so Jude's factorization is correct.
Examine Yasmin's Factorization: Now let's examine Yasmin's factorization of 28x2: Yasmin factored 28x2 as (7x)(4x). To check if this is correct, we multiply the factors together: (7x)×(4x)=28x2. This is also the original expression, so Yasmin's factorization is correct as well.
Verify Correct Factorizations: Since both Jude and Yasmin have factored 28x2 correctly, the answer to the question is that both of them factored it correctly.
More problems from Quantities that combine to zero: word problems