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If 
3^(a)=root(5)(3^(2)), what is the value of 
a ?

If 3a=325 3^{a}=\sqrt[5]{3^{2}} , what is the value of a a ?

Full solution

Q. If 3a=325 3^{a}=\sqrt[5]{3^{2}} , what is the value of a a ?
  1. Given Equation: We are given the equation 3a=3253^{a} = \sqrt[5]{3^{2}}. To solve for aa, we need to express both sides of the equation with the same base and then compare the exponents.
  2. Express with Same Base: The fifth root of 323^{2} can be written as (32)1/5(3^{2})^{1/5}. This uses the property that the nnth root of a number is the same as raising that number to the power of 1/n1/n.
  3. Simplify Right Side: Now we have 3a=(32)1/53^{a} = (3^{2})^{1/5}. Using the property of exponents that (xm)n=xmn(x^{m})^{n} = x^{m*n}, we can simplify the right side of the equation.
  4. Set Exponents Equal: Simplify the right side: (32)15=3215=325(3^{2})^{\frac{1}{5}} = 3^{2\cdot\frac{1}{5}} = 3^{\frac{2}{5}}.
  5. Set Exponents Equal: Simplify the right side: (32)1/5=321/5=32/5(3^{2})^{1/5} = 3^{2*1/5} = 3^{2/5}.Now we have 3a=32/53^{a} = 3^{2/5}. Since the bases are the same, we can set the exponents equal to each other to find the value of aa.
  6. Set Exponents Equal: Simplify the right side: (32)15=3215=325(3^{2})^{\frac{1}{5}} = 3^{2*\frac{1}{5}} = 3^{\frac{2}{5}}.Now we have 3a=3253^{a} = 3^{\frac{2}{5}}. Since the bases are the same, we can set the exponents equal to each other to find the value of aa.Set the exponents equal: a=25a = \frac{2}{5}.

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