Q. How many solutions does the following equation have?7(y+3)=5y+8Choose 1 answer:(A) No solutions(B) Exactly one solution(C) Infinitely many solutions
Distribute the 7: Distribute the 7 to both terms inside the parentheses.7(y+3)=7⋅y+7⋅3=7y+21
Rewrite the equation: Rewrite the equation with the distributed terms. 7y+21=5y+8
Move terms with y: Move all terms containing y to one side of the equation by subtracting 5y from both sides.7y+21−5y=5y+8−5y=2y+21=8
Move constant term: Move the constant term on the y-side to the other side by subtracting 21 from both sides.2y+21−21=8−21=2y=−13
Solve for y: Solve for y by dividing both sides by 2.22y=2−13⇒y=−6.5
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