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How many solutions does the following equation have?

-5(z+1)=-2z+10
Choose 1 answer:
(A) No solutions
(B) Exactly one solution
(C) Infinitely many solutions

How many solutions does the following equation have?\newline5(z+1)=2z+10-5(z+1)=-2z+10\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions

Full solution

Q. How many solutions does the following equation have?\newline5(z+1)=2z+10-5(z+1)=-2z+10\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions
  1. Distribute 5 -5 : Distribute 5 -5 to both terms inside the parentheses.5(z+1)=5z5 -5(z+1) = -5z - 5
  2. Rewrite with distributed terms: Rewrite the equation with the distributed terms.\newline5z5=2z+10-5z - 5 = -2z + 10
  3. Add 5z5z to both sides: Add 5z5z to both sides to get all the zz terms on one side.\newline5z+5z5=2z+5z+10-5z + 5z - 5 = -2z + 5z + 10
  4. Simplify both sides: Simplify both sides of the equation. 0z5=3z+100z - 5 = 3z + 10
  5. Add 55 to isolate constant terms: Add 55 to both sides to isolate the constant terms on one side.\newline5+5=3z+10+5-5 + 5 = 3z + 10 + 5
  6. Simplify both sides: Simplify both sides of the equation. 0=3z+150 = 3z + 15
  7. Subtract 1515 to solve for z: Subtract 1515 from both sides to solve for z.\newline00 - 1515 = 33z + 1515 - 1515
  8. Simplify both sides: Simplify both sides of the equation. 15=3z-15 = 3z
  9. Divide both sides by 33: Divide both sides by 33 to solve for zz.153=3z3\frac{-15}{3} = \frac{3z}{3}
  10. Simplify both sides: Simplify both sides of the equation. 5=z-5 = z

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