How many solutions does the following equation have?−5(z+1)=−2z+10Choose 1 answer:(A) No solutions(B) Exactly one solution(C) Infinitely many solutions
Q. How many solutions does the following equation have?−5(z+1)=−2z+10Choose 1 answer:(A) No solutions(B) Exactly one solution(C) Infinitely many solutions
Distribute −5: Distribute −5 to both terms inside the parentheses.−5(z+1)=−5z−5
Rewrite with distributed terms: Rewrite the equation with the distributed terms.−5z−5=−2z+10
Add 5z to both sides: Add 5z to both sides to get all the z terms on one side.−5z+5z−5=−2z+5z+10
Simplify both sides: Simplify both sides of the equation. 0z−5=3z+10
Add 5 to isolate constant terms: Add 5 to both sides to isolate the constant terms on one side.−5+5=3z+10+5
Simplify both sides: Simplify both sides of the equation. 0=3z+15
Subtract 15 to solve for : Subtract from both sides to solve for z.\newline000 - 151515 = 333z + 151515 - 151515
Simplify both sides: Simplify both sides of the equation. −15=3z-15 = 3z−15=3z
Divide both sides by 333: Divide both sides by 333 to solve for zzz.−153=3z3\frac{-15}{3} = \frac{3z}{3}3−15=33z
Simplify both sides: Simplify both sides of the equation. −5=z-5 = z−5=z
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