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How many solutions does the following equation have?

3z+9+14 z=4z+5
Choose 1 answer:
(A) No solutions
(B) Exactly one solution
(c) Infinitely many solutions

How many solutions does the following equation have?\newline3z+9+14z=4z+53z+9+14z=4z+5\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions

Full solution

Q. How many solutions does the following equation have?\newline3z+9+14z=4z+53z+9+14z=4z+5\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions
  1. Combine like terms: Simplify the left side of the equation by combining like terms.\newline3z+9+14z3z + 9 + 14z\newline= (3+14)z+9(3 + 14)z + 9\newline= 17z+917z + 9
  2. Rewrite the equation: Rewrite the equation with the simplified left side. 17z+9=4z+517z + 9 = 4z + 5
  3. Subtract 4z4z from both sides: Subtract 4z4z from both sides to get all the zz terms on one side.\newline17z+94z=4z+54z17z + 9 - 4z = 4z + 5 - 4z\newline=(174)z+9=5= (17 - 4)z + 9 = 5\newline=13z+9=5= 13z + 9 = 5
  4. Isolate the z term: Subtract 99 from both sides to isolate the z term.\newline13z+99=5913z + 9 - 9 = 5 - 9\newline13z=413z = -4
  5. Solve for z: Divide both sides by 1313 to solve for z.\newline13z13=413\frac{13z}{13} = \frac{-4}{13}\newlinez=413z = \frac{-4}{13}

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