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How many solutions does the following equation have?

3(y+41)=3y+123
Choose 1 answer:
(A) No solutions
(B) Exactly one solution
(C) Infinitely many solutions

How many solutions does the following equation have?\newline3(y+41)=3y+1233(y+41)=3y+123\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions

Full solution

Q. How many solutions does the following equation have?\newline3(y+41)=3y+1233(y+41)=3y+123\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions
  1. Distribute the 33: Distribute the 33 on the left side of the equation to both terms inside the parentheses.\newline3(y+41)=3y+1233(y+41) = 3y + 123\newline3y+341=3y+1233\cdot y + 3\cdot 41 = 3y + 123\newline3y+123=3y+1233y + 123 = 3y + 123
  2. Observe both sides: Observe both sides of the equation to determine if they are identical.\newlineSince 3y+1233y + 123 is equal to 3y+1233y + 123, the equation is true for all values of yy.
  3. Conclude the number of solutions: Conclude the number of solutions based on the observation in Step 22.\newlineBecause the equation is true for all values of yy, the equation has infinitely many solutions.

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