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How many solutions does the following equation have?

3(x+5)=-4x+8
Choose 1 answer:
(A) No solutions
(B) Exactly one solution
(c) Infinitely many solutions

How many solutions does the following equation have?\newline3(x+5)=4x+83(x+5)=-4x+8\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions

Full solution

Q. How many solutions does the following equation have?\newline3(x+5)=4x+83(x+5)=-4x+8\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions
  1. Distribute the 33: Distribute the 33 to both terms inside the parentheses.\newline3(x+5)=4x+83(x+5) = -4x+8\newline3x+35=4x+83\cdot x + 3\cdot 5 = -4x + 8\newline3x+15=4x+83x + 15 = -4x + 8
  2. Add 4x4x to both sides: Add 4x4x to both sides to get all xx terms on one side.\newline3x+4x+15=4x+4x+83x + 4x + 15 = -4x + 4x + 8\newline7x+15=87x + 15 = 8
  3. Subtract 1515 from both sides: Subtract 1515 from both sides to isolate the x term.\newline7x+1515=8157x + 15 - 15 = 8 - 15\newline7x=77x = -7
  4. Divide both sides by 77: Divide both sides by 77 to solve for x.\newline7x7=77\frac{7x}{7} = \frac{-7}{7}\newlinex=1x = -1

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