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How many solutions does the following equation have?

23 y+50+27 y=50 y+50
Choose 1 answer:
(A) No solutions
(B) Exactly one solution
(c) Infinitely many solutions

How many solutions does the following equation have?\newline23y+50+27y=50y+5023y + 50 + 27y = 50y + 50\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions

Full solution

Q. How many solutions does the following equation have?\newline23y+50+27y=50y+5023y + 50 + 27y = 50y + 50\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions
  1. Combine like terms: Combine like terms on the left side of the equation.\newline23y+50+27y23y + 50 + 27y \newline= (23+27)y+50(23 + 27)y + 50 \newline= 50y+5050y + 50
  2. Compare left and right sides: Compare the simplified left side of the equation with the right side.\newlineThe left side is 50y+5050y + 50, and the right side is 50y+5050y + 50.\newlineSince both sides of the equation are identical, the equation is true for every value of yy.
  3. Determine number of solutions: Determine the number of solutions.\newlineBecause the equation 50y+50=50y+5050y + 50 = 50y + 50 is true for any value of yy, the equation has infinitely many solutions.

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