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How many solutions does the following equation have?

20 z-5-12 z=10 z+8
Choose 1 answer:
(A) No solutions
(B) Exactly one solution
(c) Infinitely many solutions

How many solutions does the following equation have?\newline20z512z=10z+820z - 5 - 12z = 10z + 8\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions

Full solution

Q. How many solutions does the following equation have?\newline20z512z=10z+820z - 5 - 12z = 10z + 8\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions
  1. Combine like terms: Combine like terms on the left side of the equation. \newline20z512z20z - 5 - 12z\newline= (20z12z)5(20z - 12z) - 5\newline= 8z58z - 5
  2. Rewrite with simplified left side: Rewrite the equation with the simplified left side.\newline8z5=10z+88z - 5 = 10z + 8
  3. Move terms and constants: Move all terms containing zz to one side and constant terms to the other side.8z10z=8+58z - 10z = 8 + 52z=13-2z = 13
  4. Solve for z: Solve for z by dividing both sides by 2 -2 .z=132 z = \frac{13}{-2} z=6.5 z = -6.5

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