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How many solutions does the following equation have?

-15 y+7+17 y=2y+70
Choose 1 answer:
(A) No solutions
(B) Exactly one solution
(c) Infinitely many solutions

How many solutions does the following equation have?\newline15y+7+17y=2y+70-15y + 7 + 17y = 2y + 70\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions

Full solution

Q. How many solutions does the following equation have?\newline15y+7+17y=2y+70-15y + 7 + 17y = 2y + 70\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions
  1. Combine like terms: Combine like terms on the left side of the equation.\newline15y+17y+7=2y+70-15y + 17y + 7 = 2y + 70\newlineCombine the y terms:\newline(15+17)y+7=2y+70(-15 + 17)y + 7 = 2y + 70\newline2y+7=2y+702y + 7 = 2y + 70
  2. Isolate the constant terms: Subtract 2y2y from both sides of the equation to isolate the constant terms.\newline2y+72y=2y+702y2y + 7 - 2y = 2y + 70 - 2y\newline7=707 = 70
  3. Check for validity: Check the resulting statement for validity. 7=707 = 70 is not a true statement, which means there is no value of yy that can satisfy the equation.

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