How many solutions does the following equation have?14(z+3)=14z+21Choose 1 answer:(A) No solutions(B) Exactly one solution(C) Infinitely many solutions
Q. How many solutions does the following equation have?14(z+3)=14z+21Choose 1 answer:(A) No solutions(B) Exactly one solution(C) Infinitely many solutions
Distribute 14: Distribute 14 to both terms inside the parentheses on the left side of the equation.14(z+3)=14z+42
Write down equation: Write down the equation after distribution. 14z+42=14z+21
Subtract 14z: Subtract 14z from both sides of the equation to try to isolate the variable.14z+42−14z=14z+21−14z
Simplify equation: Simplify both sides of the equation after subtraction. 42=21
Check for solution: Check if the simplified equation makes sense.Since 42=21, the equation has no solution.
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