From 1945 to 2008 , one country's per capita gross domestic product (GDPPC) increased about 6% per year, ending at $19,600. For the next few years, the growth slowed to an increase of about $1,300 per year. To the nearest dollar, how much less did the GDPPC grow during the next 6 years than it would have if it had maintained its earlier growth rate?
Q. From 1945 to 2008 , one country's per capita gross domestic product (GDPPC) increased about 6% per year, ending at $19,600. For the next few years, the growth slowed to an increase of about $1,300 per year. To the nearest dollar, how much less did the GDPPC grow during the next 6 years than it would have if it had maintained its earlier growth rate?
Calculate GDPPC growth: Calculate the GDPPC growth for the next 6 years at the earlier growth rate of 6% per year.The formula for exponential growth is P=P0(1+r)t, where P0 is the initial amount, r is the growth rate, and t is the time in years.P0=$19,600, r=6% or 0.06, and t=6 years.
Perform calculation for earlier growth rate: Perform the calculation for the earlier growth rate.P=19600(1+0.06)6P=19600(1.06)6P≈19600×1.4185P≈$(27803.60)
Calculate GDPPC growth at slowed rate: Calculate the GDPPC growth for the next 6 years at the slowed growth rate of $1,300 per year.The linear growth is calculated by adding the annual increase to the initial amount for each year.P=P0+(increase per year×number of years)P=19600+(1300×6)P=19600+7800P=27400
Calculate difference in GDPPC growth: Calculate the difference in GDPPC growth between the earlier growth rate and the slowed growth rate.Difference = GDPPC at earlier growth rate - GDPPC at slowed growth rateDifference = 27803.60 - 27400Difference ≈$403.60