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Find the missing factor 
B that makes the equality true.

{:[21y^(4)=(B)(7y^(3))],[B=◻]:}

Find the missing factor B B that makes the equality true.\newline21y4=(B)(7y3)B= \begin{array}{l} 21 y^{4}=(B)\left(7 y^{3}\right) \\ B=\square \end{array}

Full solution

Q. Find the missing factor B B that makes the equality true.\newline21y4=(B)(7y3)B= \begin{array}{l} 21 y^{4}=(B)\left(7 y^{3}\right) \\ B=\square \end{array}
  1. Identify equation and goal: Identify the given equation and the goal. We are given the equation 21y4=B7y321y^4 = B \cdot 7y^3 and we need to find the value of BB that makes this equation true.
  2. Divide by 7y37y^3: Divide both sides of the equation by 7y37y^3 to solve for BB. This gives us B=21y47y3B = \frac{21y^4}{7y^3}.
  3. Simplify right side: Simplify the right side of the equation. Divide 2121 by 77 and y4y^4 by y3y^3. This gives us B=3y(43)=3yB = 3y^{(4-3)} = 3y.
  4. Check result: Check the result to ensure there are no mathematical errors. 3y×7y3=21y43y \times 7y^3 = 21y^4, which is the original equation, so the solution is correct.

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