Divide the polynomials. Your answer should be in the form p(x)+(k)/(x) where p is a polynomial and k is an integer. (2x^(3)+7)/(x)=◻

Divide by x: Divide each term of the polynomial by x. We have the polynomial 2x^3 + 7, and we want to divide each term by x. Dividing 2x^3 by x gives us 2x^2, because x^3 divided by x is x^(3-1) = x^2. Dividing 7 by x cannot be simplified further, so it remains as 7/x.Write in required form: Write the result in the required form. The result of the division is 2x^2 + 7/x. This is already in the form p(x) + (k)/(x), where p(x) is the polynomial 2x^2 and k is the integer 7.

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Divide the polynomials.
Your answer should be in the form
p(x)+(k)/(x) where
p is a polynomial and
k is an integer.

(2x^(3)+7)/(x)=◻

Divide the polynomials. $\newline$ Your answer should be in the form $p(x)+\frac{k}{x}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{2 x^{3}+7}{x}=\square$

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Algebra 1

Powers with decimal and fractional bases

Full solution

Q. Divide the polynomials.

\newline

Your answer should be in the form

p(x)+\frac{k}{x}

where

p

is a polynomial and

k

is an integer.

\newline

\frac{2 x^{3}+7}{x}=\square

Divide by x: Divide each term of the polynomial by x. $\newline$ We have the polynomial $2x^3 + 7$ , and we want to divide each term by $x$ . $\newline$ Dividing $2x^3$ by $x$ gives us $2x^2$ , because $x^3$ divided by $x$ is $x^{3-1} = x^2$ . $\newline$ Dividing $7$ by $x$ cannot be simplified further, so it remains as $x$ $0$ .
Write in required form: Write the result in the required form. $\newline$ The result of the division is $2x^2 + \frac{7}{x}$ . $\newline$ This is already in the form $p(x) + \frac{k}{x}$ , where $p(x)$ is the polynomial $2x^2$ and $k$ is the integer $7$ .