Divide the polynomials. Your answer should be in the form p(x)+(k)/(x) where p is a polynomial and k is an integer. (5x^(2)+x+7)/(x)=◻

Step 1: Divide by x: Divide each term of the polynomial by x. We will divide each term of the polynomial 5x^2 + x + 7 by x separately. 5x^2 divided by x is 5x, because x in the denominator cancels out one x in the numerator. x divided by x is 1, because x/x is equal to 1. 7 divided by x cannot be simplified further and remains as 7/x.Step 2: Write in p(x) + (k)/(x) form: Write the result in the form p(x) + (k)/(x). The result of the division from Step 1 gives us the polynomial part p(x) as 5x + 1 and the fraction part as 7/x. So, the final answer in the required form is p(x) + (k)/(x) = (5x + 1) + (7)/(x).

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Q. Divide the polynomials. Your answer should be in the form

p(x)+\frac{k}{x}

where

p

is a polynomial and

k

is an integer.

\newline

\frac{5 x^{2}+x+7}{x}=\square

Step $1$ : Divide by x: Divide each term of the polynomial by x. $\newline$ We will divide each term of the polynomial $5x^2 + x + 7$ by $x$ separately. $\newline$ $5x^2$ divided by $x$ is $5x$ , because $x$ in the denominator cancels out one $x$ in the numerator. $\newline$ $x$ divided by $x$ is $1$ , because $x$ $0$ is equal to $1$ . $\newline$ $x$ $2$ divided by $x$ cannot be simplified further and remains as $x$ $4$ .
Step $2$ : Write in $p(x) + \frac{k}{x}$ form: Write the result in the form $p(x) + \frac{k}{x}$ . $\newline$ The result of the division from Step $1$ gives us the polynomial part $p(x)$ as $5x + 1$ and the fraction part as $\frac{7}{x}$ . $\newline$ So, the final answer in the required form is $p(x) + \frac{k}{x} = (5x + 1) + \frac{7}{x}$ .