Divide the polynomials. Your answer should be in the form p(x)+(k)/(x) where p is a polynomial and k is an integer. (x^(4)+2x^(2)-5)/(x)=◻

Question

Divide the polynomials. Your answer should be in the form  p(x)+(k)/(x) where  p is a polynomial and  k is an integer.  (x^(4)+2x^(2)-5)/(x)=◻

Bytelearn · Accepted Answer

Step 1: Divide first term of numerator: Divide the first term of the numerator by the first term of the denominator. Divide x^4 by x to get x^3. Calculation: x^4 / x = x^3Step 2: Multiply divisor and subtract: Multiply the divisor by the result from Step 1 and subtract from the original polynomial. Multiply x by x^3 to get x^4 and subtract this from the original polynomial. Calculation: (x^4 + 2x^2 - 5) - (x^4) = 2x^2 - 5Step 3: Divide first term of remaining polynomial: Divide the first term of the remaining polynomial by the first term of the divisor. Divide 2x^2 by x to get 2x. Calculation: 2x^2 / x = 2xStep 4: Multiply divisor and subtract: Multiply the divisor by the result from Step 3 and subtract from the remaining polynomial. Multiply x by 2x to get 2x^2 and subtract this from the remaining polynomial. Calculation: (2x^2 - 5) - (2x^2) = -5Step 5: Determine the remainder: Since there are no more terms in the numerator that can be divided by x, the remaining term is the remainder. The remainder is -5, which cannot be divided by x. Calculation: No further division possible.

Divide the polynomials. Your answer should be in the form $p(x)+\frac{k}{x}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{4}+2 x^{2}-5}{x}=\square$

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Divide the polynomials. Your answer should be in the form p(x)+kx p(x)+\frac{k}{x} p(x)+xk​ where p p p is a polynomial and k k k is an integer.\newlinex4+2x2−5x=□ \frac{x^{4}+2 x^{2}-5}{x}=\square xx4+2x2−5​=□

Divide the polynomials. Your answer should be in the form $p(x)+\frac{k}{x}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{4}+2 x^{2}-5}{x}=\square$