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Divide the polynomials.
Your answer should be in the form 
p(x)+(k)/(x) where 
p is a polynomial and 
k is an integer.

(3x^(3)-x-2)/(x)=

Divide the polynomials.\newlineYour answer should be in the form p(x)+kx p(x)+\frac{k}{x} where p p is a polynomial and k k is an integer.\newline3x3x2x= \frac{3 x^{3}-x-2}{x}=

Full solution

Q. Divide the polynomials.\newlineYour answer should be in the form p(x)+kx p(x)+\frac{k}{x} where p p is a polynomial and k k is an integer.\newline3x3x2x= \frac{3 x^{3}-x-2}{x}=
  1. Identify dividend and divisor: Identify the dividend and the divisor. The dividend is the polynomial 3x3x23x^3 - x - 2, and the divisor is xx.
  2. Divide each term by x: Divide each term of the polynomial by x.\newlineTo divide a polynomial by x, divide each term of the polynomial by x individually.\newline(3x3x2)/x=(3x3/x)(x/x)(2/x)(3x^3 - x - 2) / x = (3x^3 / x) - (x / x) - (2 / x)
  3. Simplify each term: Simplify each term after division.\newline3x3x=3x2\frac{3x^3}{x} = 3x^2 (since x3x=x(31)=x2\frac{x^3}{x} = x^{(3-1)} = x^2)\newlinexx=1\frac{x}{x} = 1 (since any non-zero number divided by itself is 11)\newline2x\frac{2}{x} remains as it is because 22 is not divisible by xx.\newlineSo, (3x3x2)x=3x21(2x)\frac{(3x^3 - x - 2)}{x} = 3x^2 - 1 - \left(\frac{2}{x}\right)
  4. Write final answer: Write the final answer in the required form.\newlineThe polynomial part p(x)p(x) is 3x213x^2 - 1, and the integer kk is 2-2.\newlineTherefore, the final answer is p(x)+kx=3x212xp(x) + \frac{k}{x} = 3x^2 - 1 - \frac{2}{x}.