Q. Divide the polynomials.The form of your answer should either be p(x) or p(x)+x+2k where p(x) is a polynomial and k is an integer.x+23x3+x2−4x+12=
Set up division: Set up the long division.We will use polynomial long division to divide 3x3+x2−4x+12 by x+2.
Divide first term: Divide the first term of the numerator by the first term of the denominator.Divide 3x3 by x to get 3x2.Write 3x2 above the division bar.
Multiply divisor: Multiply the entire divisor by the result from Step 2.Multiply (x+2) by 3x2 to get 3x3+6x2.
Subtract result: Subtract the result from Step 3 from the corresponding terms of the dividend.Subtract (3x3+6x2) from (3x3+x2) to get −5x2.Bring down the next term of the dividend, which is −4x, to get −5x2−4x.
Divide new leading term: Divide the new leading term of the remainder by the first term of the divisor.Divide −5x2 by x to get −5x.Write −5x above the division bar next to 3x2.
Multiply divisor again: Multiply the entire divisor by the result from Step 5.Multiply (x+2) by −5x to get −5x2−10x.
Subtract result again: Subtract the result from Step 6 from the corresponding terms of the current remainder.Subtract (−5x2−10x) from (−5x2−4x) to get 6x.Bring down the next term of the dividend, which is +12, to get 6x+12.
Bring down next term: Divide the new leading term of the remainder by the first term of the divisor.Divide 6x by x to get 6.Write 6 above the division bar next to 3x2−5x.
Divide new leading term again: Multiply the entire divisor by the result from Step 8.Multiply (x+2) by 6 to get 6x+12.
Multiply divisor again: Subtract the result from Step 9 from the corresponding terms of the current remainder.Subtract (6x+12) from (6x+12) to get 0.
Subtract result again: Write the final answer.Since there is no remainder, the final answer is just the quotient we have found.The quotient is 3x2−5x+6.
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