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Chiamaka is 
149km from the university and drives 
95km closer every hour. Valente is 
170km from the university and drives 
110km closer every hour.
Let 
t represent the time, in hours, since Chiamaka and Valente started driving toward the university.
Complete the inequality to represent the times when Valente is closer than Chiamaka to the university.

t select inequality symbol hours

Chiamaka is 149km149\text{km} from the university and drives 95km95\text{km} closer every hour. Valente is 170km170\text{km} from the university and drives 110km110\text{km} closer every hour. Let tt represent the time, in hours, since Chiamaka and Valente started driving toward the university. Complete the inequality to represent the times when Valente is closer than Chiamaka to the university. tt select inequality symbol hours

Full solution

Q. Chiamaka is 149km149\text{km} from the university and drives 95km95\text{km} closer every hour. Valente is 170km170\text{km} from the university and drives 110km110\text{km} closer every hour. Let tt represent the time, in hours, since Chiamaka and Valente started driving toward the university. Complete the inequality to represent the times when Valente is closer than Chiamaka to the university. tt select inequality symbol hours
  1. Setting up distances: Let's set up the distances from the university for Chiamaka and Valente as functions of time, tt.\newlineChiamaka's distance from the university after tt hours is: 14995t149 - 95t.\newlineValente's distance from the university after tt hours is: 170110t170 - 110t.\newlineWe want to find when Valente is closer to the university than Chiamaka, which means Valente's distance is less than Chiamaka's distance.\newlineSo, we set up the inequality: 170 - 110t < 149 - 95t.
  2. Solving the inequality: Now, we solve the inequality for tt.\newlineFirst, we'll add 110t110t to both sides and add 149149 to both sides to isolate the variable tt.\newline170 - 110t + 110t < 149 - 95t + 110t\newline170 < 149 + 15t
  3. Isolating the variable t: Next, we subtract 149149 from both sides to get the t term by itself.\newline170170 - 149149 < 1515t\newline2121 < 1515t
  4. Dividing both sides: Finally, we divide both sides by 1515 to solve for tt.\newline\frac{21}{15} < t\newline1.4 < t

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