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A monkey is swinging from a tree. On the first swing, she passes through an arc of 
20m. With each swing, she passes through an arc 
(4)/(5) the length of the previous swing.
What is the total distance the monkey has traveled when she completes her 
10^("th ") swing? Round your final answer to the nearest meter.
m

A monkey is swinging from a tree. On the first swing, she passes through an arc of 20 m 20 \mathrm{~m} . With each swing, she passes through an arc 45 \frac{4}{5} the length of the previous swing.\newlineWhat is the total distance the monkey has traveled when she completes her 10th  10^{\text {th }} swing? Round your final answer to the nearest meter.\newlinem

Full solution

Q. A monkey is swinging from a tree. On the first swing, she passes through an arc of 20 m 20 \mathrm{~m} . With each swing, she passes through an arc 45 \frac{4}{5} the length of the previous swing.\newlineWhat is the total distance the monkey has traveled when she completes her 10th  10^{\text {th }} swing? Round your final answer to the nearest meter.\newlinem
  1. Identify initial arc length: Identify the initial length of the arc for the first swing and the pattern of the decrease in the length of the arc for each subsequent swing.\newlineThe initial length of the arc for the first swing is 2020 meters. The length of each subsequent swing is (4/5)(4/5) times the length of the previous swing.
  2. Calculate total distance: Calculate the total distance traveled by the monkey over the 1010 swings using the formula for the sum of a geometric series.\newlineThe sum of a geometric series is given by Sn=a1×(1rn)/(1r)S_n = a_1 \times (1 - r^n) / (1 - r), where a1a_1 is the first term, rr is the common ratio, and nn is the number of terms.\newlineHere, a1=20ma_1 = 20\,\text{m}, r=45r = \frac{4}{5}, and n=10n = 10.
  3. Plug values into formula: Plug the values into the formula to calculate the sum of the first 1010 terms of the geometric series.S10=20×(1(45)10)145S_{10} = \frac{20 \times (1 - (\frac{4}{5})^{10})}{1 - \frac{4}{5}}
  4. Simplify expression to find sum: Simplify the expression to find the sum S10S_{10}. \newlineS10=20×(1(45)10)/(15)S_{10} = 20 \times \left(1 - \left(\frac{4}{5}\right)^{10}\right) / \left(\frac{1}{5}\right)\newlineCalculate (45)10\left(\frac{4}{5}\right)^{10} using a calculator.\newline(45)100.1073741824\left(\frac{4}{5}\right)^{10} \approx 0.1073741824\newlineNow, substitute this value into the expression.\newlineS10=20×(10.1073741824)/(15)S_{10} = 20 \times \left(1 - 0.1073741824\right) / \left(\frac{1}{5}\right)\newlineS10=20×(0.8926258176)/(15)S_{10} = 20 \times \left(0.8926258176\right) / \left(\frac{1}{5}\right)\newlineS10=20×(0.8926258176)×5S_{10} = 20 \times \left(0.8926258176\right) \times 5\newlineS10=20×4.463129088S_{10} = 20 \times 4.463129088\newlineS10=89.26258176S_{10} = 89.26258176
  5. Round final answer: Round the final answer to the nearest meter. S1089S_{10} \approx 89 meters

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