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7 watermelons cost 
$8.96.
Which equation would help determine the cost of 5 watermelons?
Choose 1 answer:
(A) 
(x)/(5)=($8.96)/(7)
(B) 
(x)/(5)=(7)/($8.96)
(c) 
(7)/(5)=(x)/($8.96)
(D) 
(5)/(x)=($8.96)/(7)
(E) None of the above

77 watermelons cost $8.96 \$ 8.96 .\newlineWhich equation would help determine the cost of 55 watermelons?\newlineChoose 11 answer:\newline(A) x5=$8.967 \frac{x}{5}=\frac{\$ 8.96}{7} \newline(B) x5=7$8.96 \frac{x}{5}=\frac{7}{\$ 8.96} \newline(C) 75=x$8.96 \frac{7}{5}=\frac{x}{\$ 8.96} \newline(D) 5x=$8.967 \frac{5}{x}=\frac{\$ 8.96}{7} \newline(E) None of the above

Full solution

Q. 77 watermelons cost $8.96 \$ 8.96 .\newlineWhich equation would help determine the cost of 55 watermelons?\newlineChoose 11 answer:\newline(A) x5=$8.967 \frac{x}{5}=\frac{\$ 8.96}{7} \newline(B) x5=7$8.96 \frac{x}{5}=\frac{7}{\$ 8.96} \newline(C) 75=x$8.96 \frac{7}{5}=\frac{x}{\$ 8.96} \newline(D) 5x=$8.967 \frac{5}{x}=\frac{\$ 8.96}{7} \newline(E) None of the above
  1. Set Up Proportion: To find the cost of 55 watermelons, we need to set up a proportion where we compare the cost of 55 watermelons to the cost of 77 watermelons.
  2. Represent Cost with Variables: Let xx represent the cost of 55 watermelons. We know that 77 watermelons cost $8.96\$8.96. We can set up the proportion as the cost of 55 watermelons (xx) over 55 is equal to the cost of 77 watermelons ($8.96\$8.96) over 77.
  3. Create Correct Equation: The correct equation that represents this situation is x5=($8.96)7\frac{x}{5} = \frac{(\$8.96)}{7}. This is because we are trying to find the cost of a different number of watermelons (55 instead of 77), so we set up a ratio comparing the cost per watermelon.
  4. Final Answer: The correct answer is therefore (A)x5=($8.96)7(A) \frac{x}{5} = \frac{(\$8.96)}{7}.

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