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(-8)-(6+30 i)= Express your answer in the form (a+bi).

(−8)−(6+30i)= (-8)-(6+30 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .

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Full solution

Q. (−8)−(6+30i)= (-8)-(6+30 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .
  1. Subtracting Complex Number: We need to subtract the complex number (6+30i)(6+30i) from the real number −8-8. To do this, we subtract the real parts and the imaginary parts separately.\newline−8−(6+30i)=(−8−6)+(−30i)-8 - (6 + 30i) = (-8 - 6) + (-30i)
  2. Performing Subtraction: Now we perform the subtraction for the real parts and the imaginary parts.\newline(−8−6)+(−30i)=−14−30i(-8 - 6) + (-30i) = -14 - 30i
  3. Expressing Result: We have expressed the result in the form a+bia+bi, where aa is the real part and bb is the coefficient of the imaginary part ii. So, the result is −14−30i -14 - 30i.

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