Q. 6=−s+77Given the equation, what is the value of 1+5(77−s) ?Choose 1 answer:(A) −739(B) −29(C) 31(D) 741
Solving the equation for : First, let's solve the given equation for .\newlineAdd s to both sides to isolate the variable on one side.\newline666 + s = 777777
Finding the value of sss: Now, subtract 666 from both sides to find the value of sss. s=77−6s = 77 - 6s=77−6 s=71s = 71s=71
Calculating the expression: Next, we need to calculate the value of the expression 1+5(77−s)1 + 5(77 - s)1+5(77−s). We already know that s=71s = 71s=71, so we can substitute this value into the expression.\newline1+5(77−71)1 + 5(77 - 71)1+5(77−71)
Performing subtraction inside parentheses: Now, let's perform the subtraction inside the parentheses.\newline1+5(6)1 + 5(6)1+5(6)
Multiplying 555 by 666: Next, we multiply 555 by 666.\newline1+5×61 + 5 \times 61+5×6\newline1+301 + 301+30
Adding 111 to 303030: Finally, we add 111 to 303030 to get the final result.\newline1+30=311 + 30 = 311+30=31
More problems from Solve linear equations: mixed review