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4100 dollars is placed in an account with an annual interest rate of 
6.5%. To the nearest tenth of a year, how long will it take for the account value to reach 18400 dollars?
Answer:

41004100 dollars is placed in an account with an annual interest rate of 6.5% 6.5 \% . To the nearest tenth of a year, how long will it take for the account value to reach 1840018400 dollars?\newlineAnswer:

Full solution

Q. 41004100 dollars is placed in an account with an annual interest rate of 6.5% 6.5 \% . To the nearest tenth of a year, how long will it take for the account value to reach 1840018400 dollars?\newlineAnswer:
  1. Identify Interest Type: Determine the type of interest being applied.\newlineSince the problem does not specify compound or simple interest, we will assume compound interest, which is more common in savings accounts.
  2. Compound Interest Formula: Identify the formula for compound interest.\newlineThe formula for compound interest is A=P(1+r/n)(nt)A = P(1 + r/n)^{(nt)}, where:\newlineAA = the amount of money accumulated after nn years, including interest.\newlinePP = the principal amount (the initial amount of money).\newlinerr = the annual interest rate (decimal).\newlinenn = the number of times that interest is compounded per year.\newlinett = the time the money is invested for, in years.
  3. Convert Interest Rate: Convert the annual interest rate from a percentage to a decimal. 6.5%6.5\% as a decimal is 0.0650.065.
  4. Assume Compounding Frequency: Assume that the interest is compounded once per year n=1n=1 for simplicity, as the problem does not specify.\newlineThis means the formula simplifies to A=P(1+r)tA = P(1 + r)^t.
  5. Set Up and Solve Equation: Set up the equation with the given values and solve for tt.18400=4100(1+0.065)t18400 = 4100(1 + 0.065)^t
  6. Isolate Exponential Part: Divide both sides by $4100\$4100 to isolate the exponential part of the equation.\newline184004100=(1+0.065)t\frac{18400}{4100} = (1 + 0.065)^t
  7. Calculate Left Side: Calculate the left side of the equation.\newline(18400/4100)=4.4878(18400 / 4100) = 4.4878
  8. Take Natural Logarithm: Take the natural logarithm of both sides to solve for tt.ln(4.4878)=ln((1+0.065)t)\ln(4.4878) = \ln((1 + 0.065)^t)
  9. Use Logarithm Properties: Use the properties of logarithms to bring down the exponent.\newlineln(4.4878)=t×ln(1+0.065)\ln(4.4878) = t \times \ln(1 + 0.065)
  10. Calculate Natural Logarithm: Calculate the natural logarithm of 1+0.0651 + 0.065.ln(1+0.065)=ln(1.065)\ln(1 + 0.065) = \ln(1.065)
  11. Perform Calculations: Perform the calculations.\newlineln(4.4878)1.5007\ln(4.4878) \approx 1.5007\newlineln(1.065)0.063014\ln(1.065) \approx 0.063014
  12. Find t Value: Divide the natural logarithm of 4.48784.4878 by the natural logarithm of 1.0651.065 to find tt.\newlinet = rac{1.5007}{0.063014}
  13. Calculate Final Answer: Calculate the value of tt.t23.82t \approx 23.82
  14. Round to Nearest Tenth: Round the answer to the nearest tenth of a year.\newlinet23.8t \approx 23.8 years

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