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41=12 d-7 What is the value of d in the equation shown?

41=12d−7 41=12 d-7 \newlineWhat is the value of d d in the equation shown?

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Full solution

Q. 41=12d−7 41=12 d-7 \newlineWhat is the value of d d in the equation shown?
  1. Given equation: Start with the given equation. \newline41=12d−741 = 12d - 7\newlineWe want to isolate dd on one side of the equation to solve for it.
  2. Isolate dd: Add 77 to both sides of the equation to move the constant term to the left side.\newline41+7=12d−7+741 + 7 = 12d - 7 + 7\newlineThis simplifies to:\newline48=12d48 = 12d
  3. Move constant term: Divide both sides of the equation by 1212 to solve for dd.\newline4812=12d12\frac{48}{12} = \frac{12d}{12}\newlineThis simplifies to:\newline4=d4 = d

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