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If (x,y)(x,y) satisfies the given system of equations, what is the value of xx?\newline2y−xamp;=0, amp;x=y+7\begin{align*} 2y - x &= 0, \ & x = y + 7 \end{align*}

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Q. If (x,y)(x,y) satisfies the given system of equations, what is the value of xx?\newline2y−x=0, x=y+7\begin{align*} 2y - x &= 0, \ & x = y + 7 \end{align*}
  1. Write Equations: Write down the given system of equations.\newline2y−x=02y - x = 0\newlinex=y+7x = y + 7
  2. Solve for y: From the first equation, solve for y in terms of x.\newline2y−x=02y - x = 0\newline2y=x2y = x\newliney=x2y = \frac{x}{2}
  3. Substitute yy into xx: Substitute the expression for yy from Step 22 into the second equation.x=(x2)+7x = \left(\frac{x}{2}\right) + 7
  4. Solve for x: Solve the equation from Step 33 for x.\newlinex=x2+7x = \frac{x}{2} + 7\newlineMultiply both sides by 22 to eliminate the fraction.\newline2x=x+142x = x + 14
  5. Isolate xx: Subtract xx from both sides to isolate xx.2x−x=142x - x = 14x=14x = 14

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