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Let’s check out your problem:
Solve for
x
x
x
:
2
x
+
16
=
a
(
x
+
8
)
2x+16=a(x+8)
2
x
+
16
=
a
(
x
+
8
)
View step-by-step help
Home
Math Problems
Algebra 1
Solve linear equations: mixed review
Full solution
Q.
Solve for
x
x
x
:
2
x
+
16
=
a
(
x
+
8
)
2x+16=a(x+8)
2
x
+
16
=
a
(
x
+
8
)
Move Terms, Constants:
Now, let's move all terms with
x
x
x
to one side and constants to the other side.
\newline
Subtract
a
x
ax
a
x
from both sides.
\newline
2
x
−
a
x
+
16
=
8
a
2x - ax + 16 = 8a
2
x
−
a
x
+
16
=
8
a
Subtract
16
16
16
, Isolate x:
Next, subtract
16
16
16
from both sides to isolate the x terms.
\newline
2
x
−
a
x
=
8
a
−
16
2x - ax = 8a - 16
2
x
−
a
x
=
8
a
−
16
Combine Like Terms:
Combine like terms by factoring out
x
x
x
.
\newline
x
(
2
−
a
)
=
8
a
−
16
x(2 - a) = 8a - 16
x
(
2
−
a
)
=
8
a
−
16
Divide to Solve for
x
x
x
:
Finally, divide both sides by
(
2
−
a
)
(2 - a)
(
2
−
a
)
to solve for
x
x
x
.
x
=
8
a
−
16
2
−
a
x = \frac{8a - 16}{2 - a}
x
=
2
−
a
8
a
−
16
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7
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y
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answer:
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(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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How many solutions does the following equation have?
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9
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x
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6
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=
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9
x
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−
9
(
x
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6
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9
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108
\newline
Choose
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answer:
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(A) No solutions
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(B) Exactly one solution
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(C) Infinitely many solutions
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x
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7
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4
x
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2
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−
6
(
x
+
7
)
=
−
4
x
−
2
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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How many solutions does the following equation have?
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4
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7
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6
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\newline
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answer:
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(A) No solutions
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(B) Exactly one solution
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17
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17
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\newline
Choose
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answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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Question
How many solutions does the following equation have?
\newline
9
z
−
6
+
7
z
=
16
z
−
6
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9
z
−
6
+
7
z
=
16
z
−
6
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
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(B) Exactly one solution
\newline
(C) Infinitely many solutions
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