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2(x+55)(x-17)=0
What are the solutions to the given equation?
Choose 1 answer:
(A) 
x=-55 and 
x=17
(B) 
x=-55,x=-2, and 
x=17
(c) 
x=-17 and 
x=55
(D) 
x=-17,x=2, and 
x=55

2(x+55)(x17)=0 2(x+55)(x-17)=0 \newlineWhat are the solutions to the given equation?\newlineChoose 11 answer:\newline(A) x=55 x=-55 and x=17 x=17 \newline(B) x=55,x=2 x=-55, x=-2 , and x=17 x=17 \newline(C) x=17 x=-17 and x=55 x=55 \newline(D) x=17,x=2 x=-17, x=2 , and x=55 x=55

Full solution

Q. 2(x+55)(x17)=0 2(x+55)(x-17)=0 \newlineWhat are the solutions to the given equation?\newlineChoose 11 answer:\newline(A) x=55 x=-55 and x=17 x=17 \newline(B) x=55,x=2 x=-55, x=-2 , and x=17 x=17 \newline(C) x=17 x=-17 and x=55 x=55 \newline(D) x=17,x=2 x=-17, x=2 , and x=55 x=55
  1. Apply zero product property: First, we need to apply the zero product property, which states that if a product of factors equals zero, then at least one of the factors must be zero.\newline2(x+55)(x17)=02(x+55)(x-17) = 0\newlineWe can ignore the 22, as it does not affect the solutions for xx.\newline(x+55)(x17)=0(x+55)(x-17) = 0
  2. Set first factor equal to zero: Now, we set each factor equal to zero and solve for x.\newlineFirst factor: x+55=0x + 55 = 0\newlineSubtract 5555 from both sides to solve for x.\newlinex+5555=055x + 55 - 55 = 0 - 55\newlinex=55x = -55
  3. Set second factor equal to zero: Next, we solve for x using the second factor.\newlineSecond factor: x17=0x - 17 = 0\newlineAdd 1717 to both sides to solve for x.\newlinex17+17=0+17x - 17 + 17 = 0 + 17\newlinex=17x = 17

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